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Table 4: 

AllFeet-Right prefers that when two prosodic words are parsed, they are balanced in size. Violations are separated by prosodic word.

/σσσσσσσσ/AllFt-R
  a. [(σ)][(σ)(σσ)(σσ)(σσ)] 0 + 12 = 12 
  b. [(σ)][(σσ)(σ)(σσ)(σσ)] 0 + 11 = 11 
  c. [(σ)][(σσ)(σσ)(σ)(σσ)] 0 + 10 = 10 
  d. [(σ)][(σσ)(σσ)(σσ)(σ)] 0 + 9 = 9 
  e. [(σσ)][(σσ)(σσ)(σσ)] 0 + 6 = 6 
  f. [(σ)(σσ)][(σ)(σσ)(σσ)] 2 + 6 = 8 
  g. [(σ)(σσ)][(σσ)(σ)(σσ)] 2 + 5 = 7 
  h. [(σ)(σσ)][(σσ)(σσ)(σ)] 2 + 4 = 6 
  i. [(σσ)(σ)][(σ)(σσ)(σσ)] 1 + 6 = 7 
  j. [(σσ)(σ)][(σσ)(σ)(σσ)] 1 + 5 = 6 
  k. [(σσ)(σ)][(σσ)(σσ)(σ)] 1 + 4 = 5 
→ l. [(σσ)(σσ)][(σσ)(σσ)] 2 + 2 = 4 
/σσσσσσσσ/AllFt-R
  a. [(σ)][(σ)(σσ)(σσ)(σσ)] 0 + 12 = 12 
  b. [(σ)][(σσ)(σ)(σσ)(σσ)] 0 + 11 = 11 
  c. [(σ)][(σσ)(σσ)(σ)(σσ)] 0 + 10 = 10 
  d. [(σ)][(σσ)(σσ)(σσ)(σ)] 0 + 9 = 9 
  e. [(σσ)][(σσ)(σσ)(σσ)] 0 + 6 = 6 
  f. [(σ)(σσ)][(σ)(σσ)(σσ)] 2 + 6 = 8 
  g. [(σ)(σσ)][(σσ)(σ)(σσ)] 2 + 5 = 7 
  h. [(σ)(σσ)][(σσ)(σσ)(σ)] 2 + 4 = 6 
  i. [(σσ)(σ)][(σ)(σσ)(σσ)] 1 + 6 = 7 
  j. [(σσ)(σ)][(σσ)(σ)(σσ)] 1 + 5 = 6 
  k. [(σσ)(σ)][(σσ)(σσ)(σ)] 1 + 4 = 5 
→ l. [(σσ)(σσ)][(σσ)(σσ)] 2 + 2 = 4 
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