b) **Situation 2** (Lines 10–18 in Algorithm 2). Here is a
simple example: suppose the labels of three parent individuals are (1,1,2),
(2,3,4), and (3,5,4), respectively. As shown in Table 2, according to *Rp*, there are four
“1”s. Thus the label of the offspring individual will be
(1,2,3,4), which is no longer a triplet $(I,J,K)$.
Then, according to *Dp*, the response strategies
corresponding to labels 1, 2, 3, 4 will have a negative redundancy
($-$1/3).
Therefore, we will randomly select three labels from 1, 2, 3, and 4 to
obtain the label of the offspring individual; that is, the offspring
individual in this situation will be labeled as (1,2,3) or (1,2,4) or
(1,3,4) or (2,3,4).

Table
2:

. | RDI . | MDI . | LPS . | FPS . | PPS . |
---|---|---|---|---|---|

ML | 1 | 2 | 3 | 4 | 5 |

NL | 2 | 2 | 2 | 2 | 1 |

p | 2/9 | 2/9 | 2/9 | 2/9 | 1/9 |

Ap (Rp) | 2/3 (1) | 2/3 (1) | 2/3 (1) | 2/3 (1) | 1/3 (0) |

Dp | $-$1/3 | $-$1/3 | $-$1/3 | $-$1/3 | 1/3 |

. | RDI . | MDI . | LPS . | FPS . | PPS . |
---|---|---|---|---|---|

ML | 1 | 2 | 3 | 4 | 5 |

NL | 2 | 2 | 2 | 2 | 1 |

p | 2/9 | 2/9 | 2/9 | 2/9 | 1/9 |

Ap (Rp) | 2/3 (1) | 2/3 (1) | 2/3 (1) | 2/3 (1) | 1/3 (0) |

Dp | $-$1/3 | $-$1/3 | $-$1/3 | $-$1/3 | 1/3 |

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